calc
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wolfpac444
- Your Friendly Admin
- Posts: 1890
- Joined: 24 Mar 2003 00:07
Heh, what a messy problem. Although, the solution does combine a lot of concepts.
First off, you'll want to break it up into things which are a bit more manageable. Think partial fractions.
In the end, you should get something like four terms.
1) Super straightforward.
2) Standard integral you've seen a lot of before + chain rule
3) Messy trig sub.
4) Integration by parts where one of the parts is the one in part 3.
Hope that guides you down the right path.
First off, you'll want to break it up into things which are a bit more manageable. Think partial fractions.
In the end, you should get something like four terms.
1) Super straightforward.
2) Standard integral you've seen a lot of before + chain rule
3) Messy trig sub.
4) Integration by parts where one of the parts is the one in part 3.
Hope that guides you down the right path.
Mike Hansen
What kind of rotton bastard would ask you that!? Mike's reply is (of course) correct, but for the sake of verifying some extraordinarily tedius work...
Maple wrote:x-(1/3)*ln(x+1)+(1/6)*ln(x^2-x+1)-(1/3)*sqrt(3)*arctan((1/3)*(2*x-1)*sqrt(3))
Colin Kennedy
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